Repair vs. replace threshold table
A quick first-pass way to ask: how large a repair can make financial sense if replacement costs more each year and the repair is expected to buy additional usable life?
The simple rule behind the table
First-pass repair threshold = annual replacement premium × additional years the repair is expected to buy.
This is intentionally simplified. It is useful for orientation, not as a final verdict. A full decision also needs depreciation or resale value, maintenance, operating cost, financing, later replacement timing, reliability, safety, and the actual comparison horizon.
Make your own threshold
First-pass repair threshold: $6,000
If the repair costs materially less than this simplified threshold, repair deserves a closer look. If it costs materially more, replacement deserves a closer look. Do not use this alone for safety-critical or reliability-critical decisions.
Quick reference table
| Replacement annual premium | 1 year bought | 2 years bought | 3 years bought | 4 years bought | 5 years bought |
|---|---|---|---|---|---|
| $1,000/yr | $1,000 | $2,000 | $3,000 | $4,000 | $5,000 |
| $2,000/yr | $2,000 | $4,000 | $6,000 | $8,000 | $10,000 |
| $3,000/yr | $3,000 | $6,000 | $9,000 | $12,000 | $15,000 |
| $4,000/yr | $4,000 | $8,000 | $12,000 | $16,000 | $20,000 |
| $5,000/yr | $5,000 | $10,000 | $15,000 | $20,000 | $25,000 |
Worked example
Suppose replacement would cost about $3,000 more per year than keeping the current item, and a repair is reasonably expected to buy two additional years. The simplified threshold is $6,000. A $2,500 repair is not automatically a good decision, but it is well below that first-pass threshold and deserves a full comparison rather than an automatic replacement.
For a car, use the Car Repair vs. Replace Calculator to include depreciation, future repairs, replacement purchase cost, maintenance, operating cost, and end value.
Why this is better than “never repair above X% of value”
A fixed percentage of current value ignores the cost of the alternative. A $3,000 repair can be irrational for one vehicle and financially reasonable for another if the realistic replacement path is much more expensive. The relevant comparison is the cost of the two paths over the same period—not the repair bill in isolation.
Where the shortcut breaks
- The repair may not buy the expected life.
- The replacement may have materially different operating or maintenance cost.
- Safety or reliability can dominate the financial comparison.
- Resale value and depreciation can materially change the result.
- Financing and transaction costs can make replacement more expensive than it first appears.
Share or cite this framework
Download the example table as CSV. Illustrative arithmetic only; not a recommendation.
When referencing this table, link to this page so readers can see the assumptions and limitations. Last reviewed: October 1, 2026.